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\F3\CCOMPUTER SCIENCE DEPARTMENT
\CSTANFORD UNIVERSITY
\CCS 206 COMPUTING WITH SYMBOLIC EXPRESSIONS FALL 1973
\CFINAL EXAM
\F0\COpen Books and Notes
\J1. \F1alt\F0[\F1u, m, n\F0] takes every \F1n\F0th element of the list
\F1u\F0 starting with the \F1m\F0th. Write a recursive defintion of
\F1alt\F0[\F1u, m, n\F0].
2. \F1odds u\F0 is a list of the elements of the list \F1u\F0 that occur
in \F1u\F0 an odd number of times. Write the fastest definition of
\F1odds u\F0 that you can. Give several if you like, but be sure to have
one that works.
3. Let a graph \F1g\F0 be described as in chapter 1 of the notes and
suppose that whenever there is an edge from \F1x\F0 to \F1y\F0 there is
also an edge from \F1y\F0 to \F1x\F0. A component of the graph is a
collection of vertices which are all connected to each other by edge paths
but not connected to any other vertices. Write a function to determine
the number of components.
4. The \F1n\F0th Fibonacci number is defined by the equations\.
F\F20\F0 = 1
F\F21\F0 = 1
F\F2n+2\F0 = F\F2n+1\F0 + F\F2n\F0.
\JThus we have F\F22\F0 = 2, F\F23\F0 = 3, F\F24\F0 = 5, F\F25\F0 = 8, etc.
This definition translates into LISP as\.
F\F2n\F0 ← \F4if\F1 n\F0 = 0 \F4∨ \F1n\F0 = 1 \F4then\F0 1 \F4else\F0 F\F2n-2\F0 + F\F2n-1\F0.
\J What bad thing will happen if we try to compute F\F2100\F0 using this definition?
Write a new LISP definition of F\F2n\F0 not suffering from this problem.
5. Do \F4one\F0 of a and b.
a. Compare the the compilation of ∧'s and ∨'s in LCOM0 and
LCOM4. Give the simplest example you can of an expression for which
LCOM4 generates better code indicating the code generated by each.
b. The definition of \F1ter\F0 in TICTAC2.LSP is not very
elegant and not very efficient. Essentially the same thing is done
better in the definition of \F1win\F0. Revise \F1ter\F0 accordingly.
Likewise revise \F1imval\F0.\.
\\M0BASL30;\M1BASI30;\M2SUB;\M3NGR40;\M4BDB30;\.
\F3\CCOMPUTER SCIENCE DEPARTMENT
\CSTANFORD UNIVERSITY
\CCS 206 COMPUTING WITH SYMBOLIC EXPRESSIONS FALL 1973
\CFINAL EXAM
\CSolutions to Problems
\F0
1. \F1alt[u,m,n] ← \F4if n \F1u \F4then \F0NIL \F4else if \F1m=1 \;
\F4then a \F1u . alt[\F4d \F1u,n,n] \F4else \F1alt[\F4d \F1u,m-1,n].